A 4 kg object is moving horizontally with a speed of 5 m/s. To increase its speed to 10 m/s, the amount of net work required to be done on this object is:
A. 150 J
B. 100 J
C. 50 J
D. 75 J
Answer: Option A
Solution (By Examveda Team)
m=4 kgu=5 m/s
v=10 m/s
according to work energy theorem
w=1/2*m*(v2-u2)
w=1/2*4*(102-52)
w=1/2*4*(100-25)
w=2×75
w=150 J

Join The Discussion