A and B are two alloys in which ratios of gold and copper are 5 : 3 and 5 : 11 respectively. If these equally amount of two alloys are melted and made alloy C. What will be the ratio of gold and copper in alloy C?

Ratio of Gold and Copper in Alloy A = 5 : 3
Ratio of Gold and Copper in Alloy B = 5 : 11
Amount of Gold in Alloy A = $$\frac{5}{8}$$
Amount of Gold In Alloy B = $$\frac{5}{{16}}$$
Amount of Copper in A = $$\frac{3}{8}$$
Amount of Copper in B = $$\frac{{11}}{{16}}$$
Amount of Gold In C,
= (Amount of gold in A + Amount of gold in B) = $$\frac{5}{8}$$ + $$\frac{5}{{16}}$$ = $$\frac{{10 + 5}}{{16}}$$ = $$\frac{{15}}{{16}}$$
Amount of Copper in C,
= Amount of Copper in A + Amount of Copper in B = $$\frac{3}{8}$$ + $$\frac{{11}}{{16}}$$ = $$\frac{{17}}{{16}}$$
So,
Ratio of Gold and Copper in C,
$$ = \frac{{15}}{{16}}:\frac{{17}}{{16}} = 15:17$$