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A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ________
Answer & Solution
Correct Answer:
Option
A
Work done = 1/2*m*V2
=1/2*4*52
= 1/2*4*25
= 2*25
= 50 J
=1/2*4*52
= 1/2*4*25
= 2*25
= 50 J
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