?
A box contains 6 white, 2 black and 3 red balls. If a ball is drawn at random, what is the probability that it will not be white?
Answer & Solution
Correct Answer:
Option
A
Total balls ⇒ 6 + 2 + 3 = 11 balls
$$\eqalign{ & P\left( W \right) = \frac{6}{{11}} \cr & P\left( {{\text{not white ball}}} \right) = 1 - \frac{6}{{11}} = \frac{5}{{11}} \cr} $$
$$\eqalign{ & P\left( W \right) = \frac{6}{{11}} \cr & P\left( {{\text{not white ball}}} \right) = 1 - \frac{6}{{11}} = \frac{5}{{11}} \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login