A cricketer scored some runs in his 21st innings, as a result, his average runs increased by 3. If the present average run is 40, how many runs he scored in the final innings?

840 minus 740 because avg before 21st inns was 37 and after 21st inns avg went to 40

37×20 kaise aaya

Let's solve the problem step by step.

Let's assume the cricketer scored "X" runs in his 21st innings.

According to the given information, after the 21st innings, his average runs increased by 3. This means that his average before the 21st innings was 40 - 3 = 37 runs.

We can set up an equation using the information:

((20 * 37) + X) / 21 = 40

To solve for X, we can multiply both sides of the equation by 21:

20 * 37 + X = 40 * 21
740 + X = 840

Next, we can subtract 740 from both sides of the equation:

X = 840 - 740
X = 100

Therefore, the cricketer scored 100 runs in his final innings.

The correct answer is B. 100.

Evaluate 25% of 480 +45%of320

Average score in 20 Innings=40
Average score in 21 Innings =(40+3)=43
suppose x runs score in last inning
now,
20*40+x=43*21
x=103

He said after playing the 21 st innings his average runs are increased by 3 . 40 is the average of 20 innings .
(43*21)-(40*20)=103
So I got 103 as the answer

See, here they said that "the present average run is 40" i.e., the average of 21 innings is given 40, and since it was increased by 3 that means that it was 37 for 20 innings earlier. Thus the equation becomes what mentioned in the above answer.

37 kah se aya