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A person borrowed 1,200 at 8% per annual and Rs. 1,800 at 10% per annum, as simple interest for the same period. He had to pay Rs. 1380 in all as interest. Find the time? (in year)
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& \frac{{1200 \times t \times 8}}{{100}} + \frac{{1800 \times t \times 10}}{{100}} = 1380 \cr
& 96t + 180t = 1380 \cr
& 276t = 1380 \cr
& t = 5 \cr} $$
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