A pot has 2 white, 6 black, 4 grey and 8 green balls. If one ball is picked randomly from the pot, what is the probability of it being black or green?
A. $$\frac{{3}}{{4}}$$
B. $$\frac{{7}}{{10}}$$
C. $$\frac{{4}}{{3}}$$
D. $$\frac{{1}}{{10}}$$
Answer: Option B
Solution(By Examveda Team)
We want black or green ballThere are 6 black and 8 green balls
Total balls = 2 + 6 + 4 + 8 = 20
So Probability $$ = \frac{6}{{20}} + \frac{8}{{20}} = \frac{7}{{10}}$$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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