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A pot has 2 white, 6 black, 4 grey and 8 green balls. If one ball is picked randomly from the pot, what is the probability of it being black or green?
Answer & Solution
Correct Answer:
Option
B
We want black or green ball
There are 6 black and 8 green balls
Total balls = 2 + 6 + 4 + 8 = 20
So Probability $$ = \frac{6}{{20}} + \frac{8}{{20}} = \frac{7}{{10}}$$
There are 6 black and 8 green balls
Total balls = 2 + 6 + 4 + 8 = 20
So Probability $$ = \frac{6}{{20}} + \frac{8}{{20}} = \frac{7}{{10}}$$
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