An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank and g = Acceleration due to gravity)

A. $$\tan \theta = \frac{{\text{a}}}{{\text{g}}}$$

B. $$\tan \theta = \frac{{2{\text{a}}}}{{\text{g}}}$$

C. $$\tan \theta = \frac{{\text{a}}}{{2{\text{g}}}}$$

D. $$\tan \theta = \frac{{{{\text{a}}^2}}}{{2{\text{g}}}}$$

Answer: Option A