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Approximately how many times was the total investment in 1995 and 1996 in district B was that of total investment of district A in the same years?
Answer & Solution
Correct Answer:
Option
B
Total investment of A
= 2923.1 + 3489.5
= 6412.6
Total investment of B
= 7081.6 + 8352
= 15433.6
∴ Times = $$\frac{15433.6}{6412.6}$$ = 2.4 (Approx)
= 2923.1 + 3489.5
= 6412.6
Total investment of B
= 7081.6 + 8352
= 15433.6
∴ Times = $$\frac{15433.6}{6412.6}$$ = 2.4 (Approx)
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