91
$$\left( {{3^{25}} + {3^{26}} + {3^{27}} + {3^{28}}} \right)$$ is divisible by :
Answer & Solution
Answer: Option
D
Solution:
$$\eqalign{
& \left( {{3^{25}} + {3^{26}} + {3^{27}} + {3^{28}}} \right)\, \cr
& = {3^{25}}\left( {{3^0} + {3^1} + {3^2} + {3^3}} \right)\, \cr
& = {3^{25}} \times 40 \cr
& = {3^{24}} \times 120 \cr
& {\text{now check with option }} \cr
& {\text{Only 30 can divide this}}{\text{.}} \cr} $$