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1
Which of the following digits will replace the H marks in the following equation ?
9H + H8 + H6 = 230
Discuss
Answer & Solution
Answer: Option E
Solution:
9H + H8 + H6 = 230
⇒ {(9 × 10) + H} + (10H + 8) + (10H + 6) = 230
⇒ 21H + 104 = 230
⇒ 21H = 126
⇒ H = 6
2
What least number must be added to 1056 to get a number exactly divisible by 23 ?
Discuss
Answer & Solution
Answer: Option A
Solution:
On dividing 1056 by 23, we get 21 as remainder.
∴ Required number to be added = (23 - 21) = 2
3
If a and b are positive integers, a > b and (a + b)2 - (a - b)2 > 29
Then the smallest value of a is -
Discuss
Answer & Solution
Answer: Option B
Solution:
Since (a + b)2 - (a - b)2 = 4ab, So, the given expression should be a multiple of 4
So, the least value of 4ab is 32 and so the least value of ab is 8
Hence, the smallest value of a is 4 and that of b is 2
Hence, a = 4
4
The digit in the unit's place of the number (67)25 - 1 must be -
Discuss
Answer & Solution
Answer: Option B
Solution:
Unit digit of (67)25 = Unit digit of 725
Unit digit of 74 is 1 and so the unit digit of (74)6 is 1
∴ Unit digit of 725 = (1 × 7) = 7
Hence, the unit digit of (725 - 1) is (7 - 1) = 6
5
287 × 287 + 269 × 269 - 2 × 287 × 269 = ?
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & \left( {287 \times 287 + 269 \times 269 - 2 \times 287 \times 269} \right) \cr & = {\left( {287} \right)^2} + {\left( {269} \right)^2} - \left( {2 \times 287 \times 269} \right) \cr & = {\left( {287 - 269} \right)^2} \cr & = {\left( {18} \right)^2} \cr & = 324 \cr} $$
[∵ a2 + b2 - 2ab = (a - b)2 ]
6
What number should replace M in this multiplication problem ?
Number System mcq question image
Discuss
Answer & Solution
Answer: Option A
Solution:
Clearly, M = 0,
since 304 × 4 = 1216
7
397 × 397 + 104 × 104 + 2 × 397 × 104 = ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Given expression,
= (397)2 + (104)2 + 2 × 397 × 104
= (397 + 104)2
= (501)2
= (500 + 1)2
= (500)2 + 12 + 2 × 500 × 1
= 250000 + 1 + 1000
= 251001
8
$$\sqrt 2 $$   is a/an -
Discuss
Answer & Solution
Answer: Option C
Solution:
Since, $$\sqrt 2 $$  is a non-terminating and non-repeating decimal, so it is an irrational number.
9
If a number is divisible by both 11 and 13, then it must be necessarily :
Discuss
Answer & Solution
Answer: Option B
Solution:
We know that 11 and 13 are co-prime
So, a number divisible by both 11 and 13 will be divisible by (11 × 13)
10
What is sum of all natural numbers from 1 to 100 ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Required sum
$$\eqalign{ & = \frac{{100}}{2}\left[ {1 + 100} \right] \cr & = 101 \times 50 \cr & = 5050 \cr} $$