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91
A litre of water evaporates from 6L of sea water containing 4% salt. Find the percentage of salt in the remaining solution.
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Quantity of salt in 6L of sea water,}} \cr & = \frac{{ {6 \times 4} }}{{100}} = 0.24 \cr & {\text{Percentage of salt in 5L of sea water,}} \cr & = \frac{{ {0.24 \times 100} }}{5} = 4\frac{4}{5}\% \cr} $$
92
Two discount of 8% and 12% are equal to a single discount of:
Discuss
Answer & Solution
Answer: Option B
Solution:
After first discount,
100 ---- 8%↓ ----> 92
After second discount,
92 ---- 12%↓ ----> 80.96
Single discount = 100 - 80.96 = 19.04%
93
In a library 60% of the books are in Hindi, 60% of the remaining books are in English rest of the books are in Urdu. If there are 3600 books in English, then total no. of books in Urdu are:
Discuss
Answer & Solution
Answer: Option A
Solution:
Let there are X books in the library.
Number of Hindi books = 60% of X = $$\frac{{60{\text{X}}}}{{100}}$$  = 0.6X
Remaining Books = X - 0.6X = 0.4X
Number English books = 40% of reaming books = 60% of 0.4X = 0.24X.
Urdu Books = X-0.6X -0.24X = 0.16X
Given,
0.24X = 3600
X $$ = \frac{{3600}}{{0.24}} = 15000$$
Urdu Books = 0.16X = 0.16 × 15000 = 2400
94
In Sabarmati Express, there as many wagons as there are the no. of seats in each wagon and not more than one passenger can have the same berth (seat). If the middlemost compartment carrying 25 passengers is filled with 71.428% of its capacity, then find the maximum no. of passengers in the train that can be accommodated if it has minimum 20% seats always vacant.
Discuss
Answer & Solution
Answer: Option C
Solution:
Total number of passenger in each compartment = $$\frac{{ {25 \times 7} }}{5}$$  = $$35$$
Total berth = 352 = 1225
Maximum available capacity
$$\eqalign{ & = \frac{{ {1225 \times 80} }}{{100}} \cr & = 980\,{\text{seats}} \cr} $$
95
The population of a village is 5000 and it increases at the rate of 2% every year. After 2 years, the population will be:
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & {\text{Population after two years}}, \cr & = 5000 \times {\left[ {1 + {\frac{2}{{100}}} } \right]^2} \cr & = 5202 \cr & {\text{Alternatively}}, \cr & 5000 = = 2\% \uparrow \Rightarrow 5100 = = 2\% \uparrow \Rightarrow 5202 \cr} $$
96
In a class, the no. of boys is more than the no. of girls by 12% of the total strength. The ratio of boys and girls is:
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the no. of total student in the class = 100 and number of boy = X
and 12% of the 100 is 12
Number of girl is x - 12
total number of student is x + (x - 12) = 100
therefore x = 56.
Then,
No of boys = 56
No. of girls = 44
Boys : Girls = 56 : 44 = 14 : 11
97
In an office there were initially N employees. The HR manager first hired P% employees then after a month Q% employees left the office, the value of (P - Q) is:
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & \frac{{\text{P}}}{{100 + {\text{P}}}} = \frac{{\text{Q}}}{{100}} \cr & {\text{or}},\,100\left( {{\text{P}} - {\text{Q}}} \right) = {\text{PQ}} \cr & {\text{or}},\,\left( {{\text{P}} - {\text{Q}}} \right) = \frac{{{\text{PQ}}}}{{100}} \cr} $$
98
The amount of work in a leather factory is increased by 50%. By what percent is it necessary to increase the number of workers to complete the new amount of work in previously planned time, if the productivity of the new labour is 25% more.
Discuss
Answer & Solution
Answer: Option C
Solution:
Men × Time = Work
100 × 1 = 100 unit work
150 × 1 = 150 unit work
Extra man power = 50
But since, new workers are $$\frac{5}{4}$$ time as efficient as existing workers
Thus,
Actual no. of workers = $$\frac{{50}}{{\frac{5}{4}}}$$ = 40 workers
% required = $$\frac{{40 \times 100}}{{100}} = 40\% $$
99
A big cube is formed by rearranging the 160 coloured and 56 non-coloured similar cubes in such a way that the expouser of the coloured cubes to the outside is minimum. The percentage of exposed area that is coloured is:
Discuss
Answer & Solution
Answer: Option B
Solution:
Total number of cubes = 160 + 56 = 216
Thus, side of cube = 6 unit
No. of cubes without exposure = (6 - 2)3 = 64
Thus 64 cubes will be inside of a big cube
Now, rest cubes = 160 - 64 = 96
No. of cubes with one face outside = 6 × (4 × 4) = 96
Required % = $$\frac{{90 \times 100}}{{216}} = 44.44\% $$
100
78% of 750 + 34% of x = 30% of 2630. Find x.
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & 78\% \,{\text{of}}\,\,750 + 34\% \,{\text{of}}\,x = 30\% \,{\text{of}}\,\,2630 \cr & or,\, {\frac{{ {78 \times 750} }}{{100}}} + \frac{{34x}}{{100}} = \left( {30 \times 2630} \right) \times 100 \cr & or,\,78 \times 750 + 34x = 30 \times 2630 \cr & or,\,34x = 78900 - 58500 \cr & or,\,x = \frac{{20400}}{{34}} \cr & {\text{Hence}},\,x = 600 \cr} $$