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Speed Time And Distance - Aptitude MCQ Questions and Solutions with Explanations

Speed Time And Distance MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Speed Time And Distance with easy and logical explanations. Speed Time And Distance MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-8 section-2

Each section contains 100 MCQs on Speed Time and Distance .
71
The distance between two places R and S is 42 km. Anita starts from R with a uniform speed of 4 km/hr towards S and at the same time Romita starts from S towards R also with some uniform speed. They meet each other after 6 hours. The speed of Romita is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let speed of Romita be x km
According to the question,
Speed Time and Distance mcq solution image
(4 + x) = $$\frac{42}{6}$$ $$\left( {{\text{S = }}\frac{{\text{D}}}{{\text{T}}}} \right)$$
4 + x = 7
x = 3 km/hr
72
Two trains 150 m and 120 m long respectively moving from opposite direction cross each other in 10 sec. If the speed of the second train is 43.2 km/hr, then the speed of the first train is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the speed of second train = x km/hr
Their relative speed in opposite direction :
= (43.2 + x) km/hr
According to the question,
$$\eqalign{ & {\text{Time = }}\frac{{{l_1} + {l_2}}}{{{\text{Speed}}}} \cr & \Rightarrow 10\sec = \frac{{\left( {150 + 120} \right){\text{m}}}}{{\left( {43.2 + x} \right) \times \frac{5}{{18}}{\text{ m/s}}}} \cr & \Rightarrow 10\sec = \frac{{270 \times 18}}{{\left( {43.2 + x} \right) \times 5}} \cr & \Rightarrow 43.2 \times 5 + 5x = 486 \cr & \Rightarrow x = \frac{{486 - 216}}{5} \cr & \Rightarrow x = 54 \cr} $$
∴ Speed of the second train = 54 km/hr
73
Two cars are moving with speed v1, v2 towards a crossing along two roads, If their distance from the crossing be 40 metres and 50 metres at an instant of time then they do not collide if their speeds are such that :
Discuss
Answer & Solution
Answer: Option B
Solution:
The two cars will collide if their speed are in the ratio of the distance to do covered by them
Ratio of distance
= 40 : 50
= 4 : 5
For the cars not to collide :
v1 : v2 $$ \ne $$ 4 : 5
74
In a race of one kilometre. A gives B a start of 100 metres and still wins by 20 seconds. But if A gives B a start of 25 seconds, B wins by 50 metres. The time taken by A to run kilometre is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the time taken by A to run 1000 metres = x seconds
Time taken by B to sun 900 metres = x + 20 seconds
Speed of A and B :
$$ = \frac{{1000}}{x},\frac{{900}}{{x + 20}}$$   respectively
According to the question,
$$\frac{{950}}{{\frac{{1000}}{x}}} - \frac{{1000}}{{\frac{{900}}{{x + 20}}}} = 25$$
(As B is the winner now)
$$\eqalign{ & \Rightarrow \frac{{950x}}{{1000}} - \frac{{1000\left( {x + 20} \right)}}{{900}} = 25 \cr & \Rightarrow \frac{{19x}}{{20}} - \frac{{10x + 200}}{9} = 25 \cr & \Rightarrow 171x - 200x - 4000 = 25 \times 20 \times 9 \cr & \Rightarrow 29x = 500 \cr & \Rightarrow x = \frac{{500}}{{29}}{\text{sec}} \cr} $$
75
A man travels 50 km at speed 25 km/hr and next 40 km at 20 km/hr and there after travel 90 km at 15 km/hr. His average speed is :
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & {\text{Average speed :}} \cr & = \frac{{{\text{Total distance }}}}{{{\text{Total time}}}} \cr & = \frac{50 + 40 + 90}{2 + 2 + 6} \cr & = \frac{180}{10} \cr & = 18{\text{ km/hr}} }$$
76
The speed of two trains are in the ratio 6 : 7. If the second train runs 364 km in 4 hours, then the speed of first train is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Given, Ratio of speed of trains = 6 : 7
Second train covers 364 kms in 4 hours
Then, its speed = $$\frac{364}{4}$$ = 91 km/hr
In the question it is given that speed of the second train = 7 units
But actual speed = 91 km/hr
i.e., 7 units → 91 km
1 unit → 13 km
Therefore,
Speed of the first train is :
= 6R
= 6 × 13
= 78 km/hr
77
2 km 5 metres is equal to ?
Discuss
Answer & Solution
Answer: Option B
Solution:
We know, 1 km = 1000 metres
⇒ 2 km 5 metres = 2 km + $$\frac{5}{1000}$$  km
= 2 km + 0.005 km
= 2.005 km
78
A jeep is chasing a car which is 5 km ahead. Their respective speeds are 90 km/hr and 75 km/hr. After how many minutes will the jeep catch the car ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Speed Time and Distance mcq solution image
Their relative speed in same direction
= (90 - 75) kmph
= 15 kmph
Time taken by jeep to catch car :
$$\eqalign{ & = \frac{5}{15} {\text{ hour}} \cr & = \frac{1}{3} {\text{ hour}} \cr & = \frac{1}{3} \times 60 {\text{ min}} \cr & = 20 {\text{ min}} \cr}$$
79
A gun is fired from a fort. A man hears the sound 10 seconds later. If the sound travels at the rate of 330 m/sec, find the distance between the fort and the man.
Discuss
Answer & Solution
Answer: Option C
Solution:
Distance between the fort and the man :
= 330 × 10
= 3300 m
= 3.3 km
80
A man goes to a place on bicycle at speed of 16 km/hr and comes back at lower speed. If the average speed is 6.4 km/hr in total, then the return speed (in km/hr) is :
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Average speed :}} \cr & {\text{ = }}\frac{{2xy}}{{x + y}} \cr & = \frac{{2 \times 16 \times y}}{{16 + y}} \cr & \Rightarrow 6.4 = \frac{{32y}}{{16 + y}} \cr & \Rightarrow 102.4 + 6.4 = 32y \cr & \Rightarrow 102.4 = 25.6y \cr & \Rightarrow y = \frac{{102.4}}{{25.6}} \cr & \Rightarrow y = 4{\text{ km/hr}} \cr} $$