ExamVeda
Login
Home

Speed Time And Distance - Aptitude MCQ Questions and Solutions with Explanations

Speed Time And Distance MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Speed Time And Distance with easy and logical explanations. Speed Time And Distance MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-9 section-3

Each section contains 100 MCQs on Speed Time and Distance .
81
A train running at $$\frac{7}{11}$$ of its own speed reached a place in 22 hours. How much time could be saved if the train would have run at its own speed ?
Discuss
Answer & Solution
Answer: Option B
Solution:
New speed = $$\frac{7}{11}$$ of usual speed
∴ New time = $$\frac{11}{7}$$ of usual time
So, $$\frac{11}{7}$$ of usual time = 22 hrs
⇒ Usual time :
= $$\frac{22 × 7}{11}$$
= 14 hrs
Hence, time saved = (22 - 14) = 8 hrs
82
A journey of 192 km between two cities take 2 hours less by a fast train than by a slow train. If the average speed of the slow train is 16 km/hr less than that of the fast train, the average speed of the fast train is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the speed of the fast train be x km/hr
Then, speed of the slow train = (x - 16) km/hr
$$\eqalign{ & \therefore \frac{{192}}{{x - 16}} - \frac{{192}}{x} = 2 \cr & \Rightarrow \frac{1}{{x - 16}} - \frac{1}{x} = \frac{1}{{96}} \cr & \Rightarrow {x^2} - 16x - 1536 = 0 \cr & \Rightarrow \left( {x - 48} \right)\left( {x + 32} \right) = 0 \cr & \Rightarrow x = 48\,\text{km/hr} \cr} $$
83
A walk at a uniform rate of 4 km an hour; and 4 hr after his start, B bicycles after him at the uniform rate of 10 km an hour. How far from the starting point will B catch A ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Distance covered by A in hrs = (4 × 4) km = 16 km
Relative speed of B w.r.t. A = (10 - 4) km/hr = 6 km/hr
Time taken to cover 16 km at relative speed :
$$\eqalign{ & = \left( {\frac{{16}}{6}} \right){\text{ hrs}} \cr & = \frac{8}{3}{\text{ hrs}} \cr} $$
Distance covered by in $$\frac{8}{3}$$ hrs
$$\eqalign{ & = \left( {10 \times \frac{8}{3}} \right){\text{ km}} \cr & {\text{ = }}\left( {\frac{{80}}{3}} \right){\text{ km}} \cr & {\text{ = 26}}{\text{.7 km}} \cr} $$
84
Train A leaves Ludhiana for Delhi at 11 am, running at the speed of 60 km/hr. Train B leaves Ludhiana for Delhi by the same route at 2 pm on the same day, running at the speed of 72 km/hr. At what time will the two trains meet each other ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Distance covered by train A from 11 am to 2 pm i.e., in 3 hours :
= (60 × 3) km
= 180 km
Relative speed :
= (72 - 60) km/hr
= 12 km/hr
Time taken to cover 180 km at relative speed :
= $$\frac{180}{12}$$ hrs
= 15 hrs
So, the two trains will meet 15 hrs after 2 pm i.e., at 5 am on the next day.
85
Rani goes to school from her house in 30 minutes. Raja takes 45 minutes in covering the same distance. Find the ratio between time taken by Rani and Raja ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Rani goes to school from her house = 30 minutes
Raja goes to school from his house = 45 minutes
Required ratio :
= 30 : 45
= 2 : 3
86
Car A travels at the speed of 65 km/hr and reaches its destination in 8 hours. Car B travels at the speed of 70 km/hr and reaches its destination in 4 hours. What is the ratio of the distance covered by car A and car B respectively ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Required ratio :
= (65 × 8) : (70 × 4)
= 520 : 280
= 13 : 7
87
How long must a driver take to drive the final 70 miles of a trip if he wants to average 50 miles an hour for the entire trip and during the first part of the trip he drove 50 miles in $$1\frac{1}{2}$$ hours ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Total distance = (57 + 50) miles = 120 miles
Average speed = 50 miles/hour
Required time of journey :
$$\eqalign{ & = \left( {\frac{{120}}{{50}}} \right){\text{ hr}} \cr & = \frac{{12}}{5}{\text{ hr}} \cr & = 2\frac{2}{5}{\text{ hr}} \cr & {\text{ = 2 hr }}24{\text{ min}} \cr} $$
Time taken to cover 50 miles :
$$\eqalign{ & = {\text{1}}\frac{1}{2}{\text{ hr}} \cr & = 1{\text{ hr 30 min}} \cr} $$
∴ Remaining time :
= (2 hr 24 min - 1 hr 30 min)
= 54 min
88
The average speed of a bus is one-third of the speed of a train. The train covers 1125 km in 15 hours. How much distance will the bus cover in 36 minutes ?
Discuss
Answer & Solution
Answer: Option E
Solution:
Speed of the train :
$$\eqalign{ & = \left( {\frac{{1125}}{{15}}} \right){\text{ km/hr}} \cr & = 75{\text{ km/hr}} \cr} $$
Speed of the bus :
$$\eqalign{ & = \left( {\frac{1}{3} \times 75} \right){\text{ km/hr}} \cr & = 25{\text{ km/hr}} \cr} $$
Distance covered by the bus in 60 min = 25 km
Distance covered by the bus in 36 min :
$$\eqalign{ & = \left( {\frac{{25}}{{60}} \times 36} \right){\text{ km}} \cr & = 15{\text{ km}} \cr} $$
89
A long distance runner run 9 laps of a 400 metres track everyday. His timings (in min) for four consecutive days are 88, 96, 89 and 87 respectively. On an average, how many metres/minutes does the runner cover ?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & {\text{Average speed :}} \cr & = \frac{{{\text{Total distance covered }}}}{{{\text{Total time taken}}}} \cr & = \left( {\frac{{4 \times 9 \times 400}}{{88 + 96 + 89 + 87}}} \right){\text{m/min}} \cr & = \left( {\frac{{14400}}{{360}}} \right){\text{m/min}} \cr & = 40{\text{ m/min}} \cr} $$
90
A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for both the trips ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Speed on return trip = 150% of 40 = 60 kmph
∴ Average speed :
$$\eqalign{ & = \left( {\frac{{2 \times 40 \times 60}}{{40 + 60}}} \right){\text{kmph}} \cr & = \left( {\frac{{4800}}{{100}}} \right){\text{kmph}} \cr & = 48{\text{ kmph}} \cr} $$