Important Theory / Shots Trick on Triangles
Section 1
Section 2
91. If the measures of the sides of triangle are (x2 - 1), (x2 + 1) and 2x cm, then the triangle would be :
92. In ΔABC, ∠C is an obtuse angle. The bisectors of the exterior angles at A and B meet BC and AC produced at D and E respectively. If AB = AD = BE, then ∠ACB = ?
93. Let ABC be an equilateral triangle and AX, BY, CZ be the altitude. Then the right statement out of the four give responses is :
94. In ΔABC, DE || AC, D and E are two points on AB and CB respectively. If AB = 10 cm and AD = 4 cm, then BE : CE is
95. If the three angles of a triangle are: $${\left(x + 15 \right)^ \circ },$$ $${\left({\frac{{6x}}{5} + 6} \right)^ \circ }$$ and $${\left({\frac{{2x}}{3} + 30} \right)^ \circ }$$ then the triangle is:
96. If in a triangle ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and $$\frac{{AD}}{{BD}}$$ = $$\frac{3}{5}$$. If AC = 4 cm, then AE is
97. In a ΔABC, ∠A + ∠B = 118°, ∠A + ∠C = 96°. Find the value of ∠A.
98. For a triangle ABC, D and E are two points on AB and AC such that AD = $$\frac{1}{4}$$ AB, AE = $$\frac{1}{4}$$ AC. If BC = 12 cm, then DE is :
99. In triangle ABC a straight line parallel to BC intersects AB and AC at D and E respectively. If AB = 2AD, then DE : BC is
100. ABC is a triangle and the sides AB, BC and CA are produced to E, F and G respectively. If ∠CBE = ∠ACF = 130°, then the value of ∠GAB is :
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