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In a ΔABC, ∠A + ∠B = 118°, ∠A + ∠C = 96°. Find the value of ∠A.
Answer & Solution
Correct Answer:
Option
D
According to question,
∠A + ∠B = 118°
∠A + ∠C = 96°
∠A = ?
As we know that
∠A + ∠B + ∠C = 180°
∠C = 180° - (∠A + ∠B)
∠C = 180° - 118°
∴ ∠C = 62°
∠A = 96° - 62°
∠A = 34°
∠A + ∠B = 118°
∠A + ∠C = 96°
∠A = ?
As we know that
∠A + ∠B + ∠C = 180°
∠C = 180° - (∠A + ∠B)
∠C = 180° - 118°
∴ ∠C = 62°
∠A = 96° - 62°
∠A = 34°
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