ExamVeda
Login
Home

As per the uncertainty principle Delta x cdot Delta p &nbsp...

This question belongs to Engineering Chemistry Atomic Structure
Atomic Structure
?

As per the uncertainty principle, $$\Delta x \cdot \Delta p$$   equals to

Answer & Solution
Correct Answer: Option B
Let's discuss the solution. Join the discussion
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.
Keep Learning

Related Questions on Atomic Structure

The de-Broglie wavelength for a He atom travelling at 1000 m/s (typical speed at room temperature) is
A. 99.7 × 10-12 m B. 199.4 × 10-12 m C. 199.4 × 10-18 m D. 99 × 10-6 m
The vibrational partition function for a molecule which can be described as a simple harmonic oscillator with fundamental frequency $$\nu $$ is given by
A. $$\exp \left( { - \frac{{h\nu }}{{{K_B}T}}} \right)$$ B. $${\left[ {1 - \exp \left( { - \frac{{h\nu }}{{{K_B}T}}} \right)} \right]^{ - 1}}$$ C. $$\exp \left( { - \frac{{h\nu }}{{{K_B}T}}} \right){\left[ {1 - \exp \left( { - \frac{{h\nu }}{{{K_B}T}}} \right)} \right]^{ - 1}}$$ D. $$\exp \left( { - \frac{{h\nu }}{{2{K_B}T}}} \right){\left[ {1 - \exp \left( { - \frac{{h\nu }}{{{K_B}T}}} \right)} \right]^{ - 1}}$$
The wave function for a quantum mechanical particle in a one-dimensional box of length a is given by $$\psi = A\sin \frac{{\pi x}}{a}.$$   The value of A for a box of length 200 nm is
A. 4 × 104 (nm)2 B. 10$$\sqrt 2 $$ (nm)1/2 C. $$\sqrt 2 $$ /10 (nm)-1/2 D. 0.1 (nm)-1/2
First order perturbation correction $$\Delta \varepsilon _n^{\left( 1 \right)}$$  to energy level $${\varepsilon _n}$$ of a simple harmonic oscillator due to the anharmonicity perturbation $$\gamma {x^3}$$ is given by
A. $$\Delta \varepsilon _n^{\left( 1 \right)} = \gamma $$ B. $$\Delta \varepsilon _n^{\left( 1 \right)} = {\gamma ^2}$$ C. $$\Delta \varepsilon _n^{\left( 1 \right)} = {\gamma ^{ - 1}}$$ D. $$\Delta \varepsilon _n^{\left( 1 \right)} = 0$$
More Related Questions on Atomic Structure