Assuming \[{\text{i}} = \sqrt { - 1} \] and t is a real number, \[\int\limits_0^{\frac{\pi }{3}} {{{\text{e}}^{{\text{it}}}}} {\text{dt}}\] is
A. \[\frac{{\sqrt 3 }}{2} + {\text{i}}\frac{1}{2}\]
B. \[\frac{{\sqrt 3 }}{2} - {\text{i}}\frac{1}{2}\]
C. \[\frac{1}{2} + {\text{i}}\left( {\frac{{\sqrt 3 }}{2}} \right)\]
D. \[\frac{1}{2} + {\text{i}}\left( {1 - \frac{{\sqrt 3 }}{2}} \right)\]
Answer: Option A

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