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At a given value of E R (ratio of activation energy...

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Chemical Reaction Engineering
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At a given value of E/R (ratio of activation energy and gas constant), the ratio of the rate constants at 500°K and 400°K is 2, if Arrhenious law is used. What will be this ratio, if transition state theory is used with the same value of E/R?

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Correct Answer: Option D
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Chintan Bhalerao
Chintan Bhalerao 5 years ago
Firstly calculate E/R by using Arrhenious Theory. Then we have the expression for transition state theory i.e. K = Te^E/RT solve the expression you will get:
ln(K2/K1) = ln(T2/T1) + E/R(1/T1 + 1/T2)
we have all the values so put the values in the equation and you will get K2/K1 = 2.5
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