At a given value of E/R (ratio of activation energy and gas constant), the ratio of the rate constants at 500°K and 400°K is 2, if Arrhenious law is used. What will be this ratio, if transition state theory is used with the same value of E/R?
A. 1.6
B. 2
C. 2.24
D. 2.5
Answer: Option D

Firstly calculate E/R by using Arrhenious Theory. Then we have the expression for transition state theory i.e. K = Te^E/RT solve the expression you will get:
ln(K2/K1) = ln(T2/T1) + E/R(1/T1 + 1/T2)
we have all the values so put the values in the equation and you will get K2/K1 = 2.5