At x = 0, the function $${\text{f}}\left( {\text{x}} \right) = \left| {\sin \frac{{2\pi {\text{x}}}}{{\text{L}}}} \right|$$ , (-$$\infty $$ < x < $$\infty $$, L > 0) is
A. continuous and differentiable
B. Not continuous and not differentiable
C. Not continuous but differentiable
D. Continuous but not differentiable
Answer: Option D

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