Applied Mechanics And Graphic Statics MCQ Questions & Answers

51

Two forces act an angle of 120°. If the greater force is 50 kg and their resultant is perpendicular to the smaller force, the smaller force is

A) 20 kg B) 25 kg C) 30 kg D) 35 kg

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Answer & Solution

Answer: Option B

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52

M.I. of solid sphere, is

A) $$\frac{2}{3}{\text{M}}{{\text{r}}^2}$$ B) $$\frac{2}{5}{\text{M}}{{\text{r}}^2}$$ C) $${\text{M}}{{\text{r}}^2}$$ D) $$\frac{1}{2}{\text{M}}{{\text{r}}^2}$$

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Answer & Solution

Answer: Option B

Solution:

The moment of inertia (II) of a solid sphere can be calculated using the formula:

I=$$\frac{2}{5}{\text{M}}{{\text{r}}^2}$$

Where:
I is the moment of inertia.
M is the mass of the sphere.
r is the radius of the sphere.

In this formula, we can see that the moment of inertia depends on both the mass of the sphere (MM) and the square of its radius (r²). The factor $$\frac{2}{5}$$ is a constant that relates to the distribution of mass within a solid sphere. This formula is specific to solid spheres and is derived from the integration of infinitesimal mass elements over the entire volume of the sphere.

So, the moment of inertia for a solid sphere is $$\frac{2}{5}$$ times the product of its mass and the square of its radius. This property is important in physics and engineering, especially when analyzing the rotational motion of objects.

53

The following is not a law of static friction:

A) The force of friction always acts in a direction opposite to that in which the body tends to move B) The force of friction is dependent upon the area of contact C) The force of friction depends upon the roughness of the surface D) The magnitude of the limiting friction bears a constant ratio to the normal reaction between two surfaces

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Answer & Solution

Answer: Option A

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54

A hoop of radius 3 m weighs 100 kg. It rolls along a horizontal floor so that at its centre of mass has a speed of 200 mm/sec. The work required to stop the hoop is

A) 2 J B) 4 J C) 6 J D) 8 J

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Answer & Solution

Answer: Option B

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55

A satellite moves in its orbit around the earth due to

A) Gravitational force B) Centripetal force C) Centrifugal force D) None of these

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Answer & Solution

Answer: Option B

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56

A satellite goes on moving along its orbit round the earth due to

A) Gravitational force B) Centrifugal force C) Centripetal force D) None of these

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Answer & Solution

Answer: Option B

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57

A bullet weighing 200 g is fired horizontally with a velocity of 25 m/sec from a gun carried on a carriage which together with the gun weighs 100 kg. The velocity of recoil of the gun, will be

A) 0.01 m/sec B) 0.05 m/sec C) 1.00 m/sec D) 1.5 m/see

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Answer & Solution

Answer: Option B

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58

Two objects moving with uniform speeds are 5 m apart after 1 second when they move towards each other and are 1 m apart when they move in the same direction.
The speeds of the objects are:

A) 2 m/sec and 2 m/sec B) 3 m/sec and 2 m/sec C) 3 m/sec and 3 m/sec D) 4 m/sec and 6 m/sec

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Answer & Solution

Answer: Option B

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59

Periodic time of a particle moving with simple harmonic motion is the time taken by the particle for

A) Half oscillation B) Quarter oscillation C) Complete oscillation D) None of these

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Answer & Solution

Answer: Option C

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60

If a particle moves with a uniform angular velocity $$\omega $$ radians/sec along the circumference of a circle of radius r, the equation for the velocity of the particle, is

A) $${\text{v}} = \omega \sqrt {{{\text{y}}^2} - {{\text{r}}^2}} $$ B) $$\overline {\text{y}} = \omega \sqrt {{\text{y}} - {\text{r}}} $$ C) $${\text{v}} = \omega \sqrt {{{\text{r}}^2} + {{\text{y}}^2}} $$ D) $${\text{v}} = \omega \sqrt {{{\text{r}}^2} - {{\text{y}}^2}} $$

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Answer & Solution

Answer: Option D

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Applied Mechanics And Graphic Statics MCQ Questions & Answers | Civil Engineering