Consider a real-valued base-band signal x(t), band limited to 10 kHz. The Nyquist rate for the signal $${\text{y}}\left( {\text{t}} \right) = {\text{x}}\left( {\text{t}} \right){\text{x}}\left( {1 + \frac{{\text{t}}}{2}} \right)$$ is
A. 15 kHz
B. 30 kHz
C. 60 kHz
D. 20 kHz
Answer: Option B

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