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Consider a real-valued base-band signal x(t), band limited to 10 kHz. The Nyquist rate for the signal $${\text{y}}\left( {\text{t}} \right) = {\text{x}}\left( {\text{t}} \right){\text{x}}\left( {1 + \frac{{\text{t}}}{2}} \right)$$     is

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Correct Answer: Option B
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