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This question belongs to Engineering Maths Calculus
Calculus
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Consider the following definite integral:
\[{\text{I}} = \int\limits_0^1 {\frac{{{{\left( {{{\sin }^{ - 1}}{\text{x}}} \right)}^2}}}{{\sqrt {1 - {{\text{x}}^2}} }}{\text{dx}}} \]
The value of the integral is

Answer & Solution
Correct Answer: Option A
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