Examveda

Consider the following definite integral:
\[{\text{I}} = \int\limits_0^1 {\frac{{{{\left( {{{\sin }^{ - 1}}{\text{x}}} \right)}^2}}}{{\sqrt {1 - {{\text{x}}^2}} }}{\text{dx}}} \]
The value of the integral is

A. \[\frac{{{\pi ^3}}}{{24}}\]

B. \[\frac{{{\pi ^3}}}{{12}}\]

C. \[\frac{{{\pi ^3}}}{{48}}\]

D. \[\frac{{{\pi ^3}}}{{64}}\]

Answer: Option A


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