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91
A capacitance of 100 uF is connected in series with a resistance of 8000 ohm. The time constant of the circuit is
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Answer: Option D
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92
Electric intensity at any point in an electric field is equal to the at that point.
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Answer: Option C
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93
A potential of 400 V is applied to a capacitor, the plates of which are 4 mm apart. The strength of electric field is
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Answer & Solution
Answer: Option A
Solution:
Let's break down this problem step-by-step to understand how to find the electric field strength.

What is Electric Field Strength?
The electric field strength (often denoted by 'E') tells us how strong the electric force is at a particular point.
Think of it like this: the higher the electric field strength, the stronger the force a charge would feel if placed there.

The Relationship Between Potential and Electric Field
When we have a uniform electric field (meaning the field is the same strength and direction everywhere), there's a simple relationship between the potential difference (voltage, 'V') and the electric field strength ('E'):

E = V / d

Where:
* 'E' is the electric field strength (what we want to find)
* 'V' is the potential difference (voltage) between the plates
* 'd' is the distance between the plates

Applying the Formula to Our Problem
We're given:
* V = 400 V (potential difference)
* d = 4 mm = 0.004 m (distance between plates - we need to convert mm to meters!)

Now, plug these values into the formula:
E = 400 V / 0.004 m
E = 100000 V/m
E = 100 kV/m (Kilovolts per meter)

Therefore, the correct answer is Option A: 100 kV/m
94
The dielectric constant (relative permittivity) of glass is given by
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Answer: Option D
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95
1 volt/meter is same as
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Answer: Option C
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96
When the dielectric is homogeneous,the potential gradient is
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Answer: Option A
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97
An electric field line and an equipotential surface are
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Answer: Option B
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98
Paper condenser is
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Answer: Option B
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99
The direction of electric field due +0 positive charge is .
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Answer: Option A
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100
The capacitance of a capacitor is not affected by
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Answer: Option C
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