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Find, the probability that if a dice is thrown twice, the sum of the digits is 10.
Answer & Solution
Correct Answer:
Option
C
Total events = 62 = 36
Sum as 10 = (6, 4)(4, 6)(5, 5)
Probability = $$\frac{3}{{36}}$$ = $$\frac{1}{{12}}$$
Sum as 10 = (6, 4)(4, 6)(5, 5)
Probability = $$\frac{3}{{36}}$$ = $$\frac{1}{{12}}$$
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