Five years ago, the average age of A, B, C and D was 45 yr. with E joining them now, the average of all the five is 49 yr. How old is E?
A. 25 years
B. 40 years
C. 45 years
D. 64 years
Answer: Option C
Solution(By Examveda Team)
Total present age of A, B, C and D= (45 × 4) + (4 × 5)
= 200 years
Total age present age of A, B, C, D and E
= 49 × 5
= 245 years
So, Age of E = 45 years
This Question Belongs to Arithmetic Ability >> Average
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Comments ( 5 )
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Ok its 45 because we have to add 5 years to the age of those four persons 5*4 exactly
49*5- 45*4= age of E =65
In the above solution why 4*5 is required because this is the simple calculation
Why (4*5) to perform ?
Avg_5yrs ago = A+B+C+D/4 = 45 (age of each person will be taken as 45)
When E joins avg becomes 49.
But as given in question person E joins 5 years later.
And the age of a person is not constant, i.e. it will change with time.
So 5 years later, the age of A, B, C, D will increase by 5 and become 50 years.
Thus, now avg of ABCD 5 yrs later will become 50.
We know that A+B+C+D+E/5 = 49, but we know the values of ABCD
hence, 50+50+50+50+E/5 = 49
E = 45 Years
65