For a matrix \[\left[ {\text{M}} \right] = \left[ {\begin{array}{*{20}{c}} {\frac{3}{5}}&{\frac{4}{5}} \\ {\text{x}}&{\frac{3}{5}} \end{array}} \right],\]    the transpose of the matrix is equal to the inverse of the matrix, [M]^T = [M]^-1. The value of x is given by

A. \[ - \frac{4}{5}\]

B. \[ - \frac{3}{5}\]

C. \[\frac{3}{5}\]

D. \[\frac{4}{5}\]

Answer: Option A