For a sleeper density of (n+5), the number of sleepers required for constructing a broad gauge railway track of length 650 m is

For Broad Gauge (BG):

Standard rail length n=13 m

Given sleeper density:

Sleeper density=n+5

So,

=13+5=18

This means 18 sleepers per rail length.

Now total track length:

650 m

Number of rail lengths:

13
650
​

=50

Total sleepers required:

50×18=900

Broad gauge length=13m
Total length of route =650m
No of rail require = 650/13
= 50 rails
No of sleepers require (n+5)= 13+5
= 18
Total sleepers require in total route = 50*18
= 900

Sleeper density = (n+5).
Length of one rail for broad gauge track 12.8 say 13(I,e n),
Sleeper density=13+5=18,
The Number of sleepers required for 650m lenth=(18/13)* 650.
=899.999 say 900.

write answer
for broad guage
length 13m
so 650/13=50
means 18 sleepers of 1 rail length .
so for 18= 18*50=900

Wrong answer correct answer is 918 check ies master for that