Given that L[ f( t ) ] = s + 2 over s^2 + 1,L[ g( t ) ] = s^2 + 1 over ( s + 3 )( s + 2 ), h( t ) = tlimits_0^t f( ) g( t - )d L[h(t)] is

This question belongs to Electronics And Communications Engineering Signal Processing

Signal Processing

Given that
$$L\left[ {f\left( t \right)} \right] = {{s + 2} \over {{s^2} + 1}},L\left[ {g\left( t \right)} \right] = {{{s^2} + 1} \over {\left( {s + 3} \right)\left( {s + 2} \right)}},$$ $$h\left( t \right) = \int\limits_0^t {f\left( \tau \right)} g\left( {t - \tau } \right)d\tau $$
L[h(t)] is

A) $${{{s^2} + 1} \over {s + 3}}$$ B) $${1 \over {s + 3}}$$ C) $${{{s^2} + 1} \over {\left( {s + 3} \right)\left( {s + 2} \right)}} + {{s + 2} \over {{s^2} + 1}}$$ D) None of the above

Answer & Solution

Correct Answer: Option B

Let's discuss the solution. Join the discussion

Question posted by Examveda

Community

Join the Discussion

Join the discussion

No comments yet Be the first to discuss this question.

Keep Learning

Given that L left f left( t right) right = s...

Given that $$L\left[ {f\left( t \right)} \right] = {{s + 2} \over {{s^2} + 1}},L\left[ {g\left( t \right)} \right] = {{{s^2} + 1} \over {\left( {s + 3} \right)\left( {s + 2} \right)}},$$ $$h\left( t \right) = \int\limits_0^t {f\left( \tau \right)} g\left( {t - \tau } \right)d\tau $$ L[h(t)] is

Join the Discussion

Related Questions on Signal Processing

Given that
$$L\left[ {f\left( t \right)} \right] = {{s + 2} \over {{s^2} + 1}},L\left[ {g\left( t \right)} \right] = {{{s^2} + 1} \over {\left( {s + 3} \right)\left( {s + 2} \right)}},$$ $$h\left( t \right) = \int\limits_0^t {f\left( \tau \right)} g\left( {t - \tau } \right)d\tau $$
L[h(t)] is