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If 0° < A < 90°, then the value of tan2A + cot2A - sec2A cosec2A is?
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& {\text{ta}}{{\text{n}}^2}{\text{A}} + {\text{co}}{{\text{t}}^2}{\text{A}} - {\sec ^2}{\text{A}}{\text{.cose}}{{\text{c}}^2}{\text{A}} \cr
& {\bf{Shortcut\,\, method:}} \cr
& {\text{Put A}} = {45^ \circ } \cr
& \Rightarrow {\text{ta}}{{\text{n}}^2}{45^ \circ } + {\text{co}}{{\text{t}}^2}{45^ \circ } - {\sec ^2}{45^ \circ }{\text{.cose}}{{\text{c}}^2}{45^ \circ } \cr
& \Rightarrow 1 + 1 - {\left( {\sqrt 2 } \right)^2}{\left( {\sqrt 2 } \right)^2} \cr
& \Rightarrow - 2 \cr} $$
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