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If A + B = C, then tanAtanBtanC = ?
Answer & Solution
Correct Answer:
Option
D
A + B = C
tan(A + B) = tanC
$$\frac{{\tan {\text{A}} + \tan {\text{B}}}}{{1 - \tan {\text{A}}\tan {\text{B}}}} = \tan {\text{C}}$$
tanA + tanB = tanC - tanAtanBtanC
tanAtanBtanC = tanC - tanA - tanB
tan(A + B) = tanC
$$\frac{{\tan {\text{A}} + \tan {\text{B}}}}{{1 - \tan {\text{A}}\tan {\text{B}}}} = \tan {\text{C}}$$
tanA + tanB = tanC - tanAtanBtanC
tanAtanBtanC = tanC - tanA - tanB
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