If cos27° = x, then the value of tan63° is?

A. $$\frac{x}{{\sqrt {1 - {x^2}} }}$$

B. $$\frac{x}{{\sqrt {1 + {x^2}} }}$$

C. $$\frac{{\sqrt {1 - {x^2}} }}{x}$$

D. $$\frac{{\sqrt {1 + {x^2}} }}{x}$$

Answer: Option A

Solution(By Examveda Team)

Given, cos27° = x

tan63° = $$\frac{x}{{\sqrt {1 - {x^2}} }}$$