If $$L\left[ {f\left( t \right)} \right] = \frac{{2\left( {s + 1} \right)}}{{\left( {{s^2} + 2s + 5} \right)}},$$ then f(0+) and f(∞) are given by
A. 0, 2 respectively
B. 2, 0 respectively
C. 0,1 respectively
D. $$\frac{2}{5},$$ 0 respectively
Answer: Option B

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