If $$\overrightarrow {\text{a}} $$ and $$\overrightarrow {\text{b}} $$ are two arbitrary vectors with magnitudes a and b, respectively, $${\left| {\overrightarrow {\text{a}} \times \overrightarrow {\text{b}} } \right|^2}$$  will be equal to

A. $${{\text{a}}^2}{{\text{b}}^2} - {\left( {\overrightarrow {\text{a}} \cdot \overrightarrow {\text{b}} } \right)^2}$$

B. $${\text{ab}} - \overrightarrow {\text{a}} \cdot \overrightarrow {\text{b}} $$

C. $${{\text{a}}^2}{{\text{b}}^2} + {\left( {\overrightarrow {\text{a}} \cdot \overrightarrow {\text{b}} } \right)^2}$$

D. $${\text{ab}} + \overrightarrow {\text{a}} \cdot \overrightarrow {\text{b}} $$

Answer: Option A