If $$\overrightarrow {\text{r}} $$ is the position vector of any point on a closed surface S that encloses volume V then $$\iint\limits_{\text{S}} {\overrightarrow {\text{r}} \cdot {\text{d}}\overrightarrow {\text{S}} }$$ is equal to
A. $$\frac{1}{2}$$V
B. V
C. 2V
D. 3V
Answer: Option D

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