If sinθ = $$\frac{9}{{41}},$$ 0° < θ < 90° then what is the value of cotθ?

A. $$\frac{{39}}{9}$$

B. $$\frac{{35}}{8}$$

C. $$\frac{{40}}{9}$$

D. $$\frac{{47}}{8}$$

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & \sin \theta = \frac{9}{{41}} \cr & \frac{P}{H} = \frac{9}{{41}},\,\,B = 40 \cr & \Rightarrow \cot \theta = \frac{B}{P} = \frac{{40}}{9} \cr} $$