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If sinθ = $$\frac{9}{{41}},$$ 0° < θ < 90° then what is the value of cotθ?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& \sin \theta = \frac{9}{{41}} \cr
& \frac{P}{H} = \frac{9}{{41}},\,\,B = 40 \cr
& \Rightarrow \cot \theta = \frac{B}{P} = \frac{{40}}{9} \cr} $$
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