If the pore diffusion controls in a catalytic reaction, the apparent activation energy Ea is equal to
A. The intrinsic activation energy E
B. E + ED where ED is activation due to diffusion
C. $$\frac{{{\text{E}} + {{\text{E}}_{\text{D}}}}}{2}$$
D. $$\frac{{{{\text{E}}_{\text{D}}}}}{2}$$
Answer: Option D

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