If the signal $$x\left( t \right) = {{\sin \left( t \right)} \over {\pi t}} * {{\sin \left( t \right)} \over {\pi t}}$$     with $$ * $$ denoting the convolution operation, then x(t) is equal to

A. $${{\sin \left( t \right)} \over {\pi t}}$$

B. $${{\sin \left( {2t} \right)} \over {2\pi t}}$$

C. $${{2\sin \left( t \right)} \over {\pi t}}$$

D. $${\left( {{{\sin \left( t \right)} \over {\pi t}}} \right)^2}$$

Answer: Option A