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This question belongs to Data Interpretation Table Chart
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Directions (1 - 5): Study the following table which shows the amount of money invested (Rupees in crore) in the core infrastructure areas of two districts. A and B of a State, and answer the below five questions.
  District A District B
Core Area 1995 1996 1995 1996
Electricity
Chemical
Thermal
Solar
Nuclear
815.2
389.5
632.4
468.1
617.9
1054.2
476.7
565.9
589.6
803.1
2065.8
745.3
1232.7
1363.5
1674.3
2365.1
986.4
1026.3
1792.1
2182.1
Total 2923.1 3489.5 7081.6 8352.0
Table Chart
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If the total investment in district B shows the same rate of increase in 1997, as it had shown from 1995 to 1996, what approximately would be the total investment in B in 1997?

Answer & Solution
Correct Answer: Option B
Difference of 1995 & 1996
= 8352 - 7081.6
= 1270.4
Increase % = $$\frac{1270.4}{7081.6}$$  × 100
                  = 17.9% (Approx)
B investment in 1997
= $$\frac{117.9}{100}$$ × 8352
= Rs. 9850 crore (Approx)
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