?
If $$\theta $$ is a positive acute angle and $$\tan 2\theta .\tan 3\theta $$ = 1 then the value of $$\left( {{\text{2co}}{{\text{s}}^2}\frac{{5\theta }}{2} - 1} \right)$$ is?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& \tan 2\theta .\tan 3\theta = 1 \cr
& \left( {2\theta + 3\theta } \right) = {90^ \circ } \cr
& 5\theta = {90^ \circ } \cr
& \left[ {{\text{If tan A}}{\text{.tan B}} = {\text{1}}} \right] \cr
& \left[ {{\text{then, A}} + {\text{B}} = {{90}^ \circ }} \right] \cr
& \Rightarrow \left( {{\text{2co}}{{\text{s}}^2}\frac{{5\theta }}{2} - 1} \right) \cr
& \Rightarrow {\text{2co}}{{\text{s}}^2}\frac{{{{90}^ \circ }}}{2} - 1 \cr
& \Rightarrow {\text{2co}}{{\text{s}}^2}{45^ \circ } - 1 \cr
& \Rightarrow \frac{{\text{2}}}{2} - 1 \cr
& \Rightarrow 0 \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login