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If xin(t) = sin(2$$\pi $$ × 4000t) + 0.75sin(2$$\pi $$ × 5000t + $$\frac{\pi }{4}$$) is sampled with Fs = 16000 Hz. Calculate X(0) if $$X\left( m \right) = \sum\nolimits_{n = 0}^{N - 1} {x\left( n \right){e^{ - \frac{{j2\pi nm}}{N}}}} .$$      When N = 8, where x(n) = xin(nts)

Answer & Solution
Correct Answer: Option B
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