If z = xy $$l$$n(xy), then
A. $${\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} + {\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}} = 0$$
B. $${\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} = {\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}}$$
C. $${\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} = {\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}}$$
D. $${\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} + {\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}} = 0$$
Answer: Option C

Join The Discussion