In a class, the number of girls is 20% more than that of the boys. The strength of the class is 66. If 4 more girls are admitted to the class, the ratio of the number of boys to that of the girls is
A. 1 : 2
B. 3 : 4
C. 1 : 4
D. 3 : 5
Answer: Option B
Solution(By Examveda Team)
Girls : boys = 6 : 5 Hence, girls = $$6 \times \frac{{66}}{{11}}$$ = 36 Boys = 30 New ratio, 30 : (36 + 4) = 3 : 4This Question Belongs to Arithmetic Ability >> Ratio
Where 11 comes from
Suppose boys=100
Girls is more than 20% of boys=120
Then 10x+12x=66
22x=66
x=3
Boys=10×=10×3=30
Girls=12x=12×3=36
4 girls are admitted in class
36+4=40
=No.of boys/No.of girls
=30/40
=3/4
Ratio=3:4
how do we take 6:5 as girls and boys ratio?
220% = 66
20% = 66*20/220
= 6
Girls = 6*120/20 = 36
Boys = 30
Ratio, 30:40 = 3:4
There are 720 students in a school the ratio of the number of boys to girl is 7:2 . if 40 new boys are admitted, find how many new girls should be admitted so that the ratio of the number of boys to the number of girls may be changed to 10:3?
Ratio is 6:5 so total 11is equal to 66 it's divisible is 6 so 6multiply by ratio. Ratio is 36:30 4 girls add so 40 : 30 ans is 4:3....
According to question
(Required Ratio)
2*15/100:3*10/100:5*20/100
2*15:3*10:5*20
3:3:10
let the number of boys is x
the number of girls = 120% of x = 120/100*x = 6x/5
so x+6x/5 = 66
11x/5 = 66
x = 30
num of boys is 30 and num of girls is 6*30/5=36
4 girls added then 36+4 =40
required ratio= 30:40 = 3:4