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In a class, the number of girls is 20% more than that of the boys. The strength of the class is 66. If 4 more girls are admitted to the class, the ratio of the number of boys to that of the girls is
Answer & Solution
Correct Answer:
Option
B
Girls : boys = 6 : 5
Hence, girls = $$6 \times \frac{{66}}{{11}}$$ = 36
Boys = 30
New ratio, 30 : (36 + 4) = 3 : 4
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Girls=66*6/11=36
Boys=66*5/11=30
New ratio=30:(36+4)=3:4
then girls 20% more than boys means = x + 20/100 of x = 6x/5
now, boys+ girls = total
x + 6x/5 = 66
11x/5 = 66
x = 30 = boys
then , girls = 6x/5 = 36
4 more girls admitted means = 36 + 4 = 40
Ratio = boys to girls = boys: girls = 30: 40 = 3:4
Girls is more than 20% of boys=120
Then 10x+12x=66
22x=66
x=3
Boys=10×=10×3=30
Girls=12x=12×3=36
4 girls are admitted in class
36+4=40
=No.of boys/No.of girls
=30/40
=3/4
Ratio=3:4
20% = 66*20/220
= 6
Girls = 6*120/20 = 36
Boys = 30
Ratio, 30:40 = 3:4
(Required Ratio)
2*15/100:3*10/100:5*20/100
2*15:3*10:5*20
3:3:10
the number of girls = 120% of x = 120/100*x = 6x/5
so x+6x/5 = 66
11x/5 = 66
x = 30
num of boys is 30 and num of girls is 6*30/5=36
4 girls added then 36+4 =40
required ratio= 30:40 = 3:4