In a lock-gate, the reaction between two gates is (where P = Resultant pressure on the lock gate and $$\alpha $$ = Inclination of the gate with the normal to the side of the lock)
A. $$\frac{{\text{P}}}{{\sin \alpha }}$$
B. $$\frac{{2{\text{P}}}}{{\sin \alpha }}$$
C. $$\frac{{\text{P}}}{{2\sin \alpha }}$$
D. $$\frac{{2{\text{P}}}}{{\sin \frac{\alpha }{2}}}$$
Answer: Option C

Assume lock gate is a simply supported beam so load is eually devided at both the supports ie p/2 sina.