In a pure inductive circuit if the supply frequency is reduced to $$\frac{1}{2},\,$$ the current will

With reference to Mr. Sunil Kumar

By Ohms Law we have
I = V/R
but here R is replaced by impedance Z
Thus, I = V/Z
and,
Z = sqrt(R^2 + XL^2)
As it is a purely inductive circuit thus, R = 0
We have Z = XL = 2πfL
now if f is halved, then XL will also be halved

But I will be doubled

I=V/X
X=2πfL
Put frequency value and compare

Plz solution of this question