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In district B, the investment in which area in 1996 did show the highest percentage increase over the investment in that area in 1995?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \text{Chemical %} \cr
& = \frac{986.4 - 745.3}{745.3} \times 100 \cr
& = \frac{241.1 \times 100}{745.3} \cr
& = 32.34\% \cr
& \cr
& \text{Solar %} \cr
& = \frac{1792.1 - 1363.5}{1363.5} \times 100 \cr
& = \frac{428.6}{1363.5} \times 100 \cr
& = 31.4\% \cr
& \cr
& \text{Electricity %} \cr
& = \frac{2365.1 - 2065.8}{2065.8} \times 100 \cr
& = \frac{299.3}{2064.8} \times 100 \cr
& = 14.4\% \cr
& \cr
& \text{Nuclear %} \cr
& = \frac{2182.1 - 1674.3}{1674.3} \times 100 \cr
& = \frac{507.8}{1674.3} \times 100 \cr
& = 30.3\% \cr} $$
So the highest percentage is in Chemical area
So the highest percentage is in Chemical area
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