In the Laurent expansion of $${\text{f}}\left( {\text{z}} \right) = \frac{1}{{\left( {{\text{z}} - 1} \right)\left( {{\text{z}} - 2} \right)}}$$ valid in the region 1 < | z | < 2, the coefficient of $$\frac{1}{{{{\text{z}}^2}}}$$ is
A. 0
B. $$\frac{1}{2}$$
C. 1
D. -1
Answer: Option D

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