Let x(t) and y(t) (with Fourier transforms X(f) and Y(f) respectively) be related as shown in the figure. Then Y(f) is

A. $$ - \frac{1}{2}X\left( {\frac{f}{2}} \right){e^{ - j2\pi f}}$$

B. $$ - \frac{1}{2}X\left( {\frac{f}{2}} \right){e^{j2\pi f}}$$

C. $$ - X\left( {\frac{f}{2}} \right){e^{j2\pi f}}$$

D. $$ - X\left( {\frac{f}{2}} \right){e^{ - j2\pi f}}$$

Answer: Option B