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Maximum value of (2sinθ + 3cosθ) is?

A. 2

B. $$\sqrt {13} $$

C. $$\sqrt {15} $$

D. 1

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & \left( {2\sin \theta + 3\cos \theta } \right) \cr & {\text{Maximum value of}} \cr & a\sin \theta + b\cos \theta \cr & = \sqrt {{a^2} + {b^2}} \cr & = \sqrt {{2^2} + {3^2}} \cr & = \sqrt {4 + 9} \cr & = \sqrt {13} \cr} $$

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