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Of four numbers whose average is 60, the first is one-fourth of the sum of the last three. The first number is -
Answer & Solution
Correct Answer:
Option
D
Let the four numbers be a, b, c and d respectively
Then,
⇒ a = $$\frac{1}{4}$$ (b + c + d)
⇒ b + c + d = 4a
Also,
a + b + c + d = 60 × 4 = 240
⇒ a + 4a = 240
⇒ 5a = 240
⇒ a = 48
Hence, first number = 48
Then,
⇒ a = $$\frac{1}{4}$$ (b + c + d)
⇒ b + c + d = 4a
Also,
a + b + c + d = 60 × 4 = 240
⇒ a + 4a = 240
⇒ 5a = 240
⇒ a = 48
Hence, first number = 48
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